Sicily 1798. Alice and Bob

判断n*n是否为偶数就行。简单的证明可以用1*2的骨牌布满棋盘。对方每走一步，你走1*2骨牌剩下的另一格，能保证必胜。

/* source code of submission 312719, Zhongshan University Online Judge System */
#include<cstdio>
using namespace std;


int main()
{
    int n;
    while ( scanf("%d", &n) && n!=0 )
    {
        if ( (n*n)%2==0 )
            printf("Alice/n");
        else 
            printf("Bob/n");
    }
    return 0;
}